Find the length and perimeter of a rectangle, whose area = 120 cm² and breadth = 8 cm.

Given:

The breadth of the rectangle is 8 cm.

The area of the rectangle is 120 cm².

Let the length of the rectangle be l.

As we know, the area of the rectangle = length x breadth

⇒ l x 8 = 120

⇒ l = $\dfrac{120}{8}$

⇒ l = 15 cm

The perimeter of the rectangle = 2(length + breadth)

= 2 (15 + 8)

= 2 x 23

= 46 cm

Hence, the length of the rectangle is 15 cm, and the perimeter is 46cm.