Find the value of (3x³) x (-5xy²) x (2x²yz³) for x = 1, y = 2 and z = 3.

(3x³) $\times$ (-5xy²) $\times$ (2x²yz³)

= (- 15x⁽³⁺¹⁾y²) $\times$ (2x²yz³)

= (- 15x⁴y²) $\times$ (2x²yz³)

= - 30x⁽⁴⁺²⁾y⁽²⁺¹⁾z³

= - 30x⁶y³z³

Putting the value x = 1, y = 2 and z = 3, we get

- 30 x 1⁶ x 2³ x 3³

= - 30 x 1 x 8 x 27

= - 6480

Hence, the value of (3x³) x (-5xy²) x (2x²yz³) for x = 1, y = 2 and z = 3 is - 6480