Find two numbers such that the sum of twice the first and thrice the second is 103 and four times the first exceeds seven times the second by 11.
Linear Equations
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Question

Find two numbers such that the sum of twice the first and thrice the second is 103 and four times the first exceeds seven times the second by 11.

KnowledgeBoat · Accepted Answer

Let two numbers be x and y. Given, Sum of twice the first and thrice the second = 103 ⇒ 2x + 3y = 103 ⇒ 2x = 103 - 3y ⇒ x = ......(1) Given, Four times the first number exceeds seven times the second by 11. ⇒ 4x - 7y = 11 ⇒ 4x = 7y + 11 .....(2) Substituting value of x from equation (1) in (2), we get : ⇒ = 7y + 11 ⇒ 2(103 - 3y) = 7y + 11 ⇒ 206 - 6y = 7y + 11 ⇒ 206 - 11 = 7y + 6y ⇒ 195 = 13y ⇒ y = . Substituting value of y in equation (1), we get : Hence, the numbers are 29 and 15.

Mathematics

Find two numbers such that the sum of twice the first and thrice the second is 103 and four times the first exceeds seven times the second by 11.

Linear Equations

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