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Mathematics

The first term of an A.P. is a and nth term is b, then the common difference of the A.P. is :

  1. ban\dfrac{b − a}{n}

  2. ban1\dfrac{b − a}{n − 1}

  3. b+an1\dfrac{b + a}{n − 1}

  4. ban+1\dfrac{b − a}{n + 1}

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Answer

Given,

First term = a

nth term = b

We know that,

an = a + (n - 1)d

⇒ b = a + (n - 1)d

⇒ b - a = (n - 1)d

⇒ d = ban1\dfrac{b - a}{n - 1}.

Hence, option 2 is the correct option.

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