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Mathematics

The first three terms of an A.P. are 3y − 1, 3y + 5 and 5y + 1 respectively. Then, the value of y is :

  1. 1

  2. 5

  3. 8

  4. 3

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Answer

Given,

The first three terms of an A.P. are 3y − 1, 3y + 5 and 5y + 1.

The difference between consecutive terms must be equal.

⇒ 3y + 5 - (3y - 1) = 5y + 1 - (3y + 5)

⇒ 3y + 5 - 3y + 1 = 5y + 1 - 3y - 5

⇒ 6 = 2y - 4

⇒ 2y = 6 + 4

⇒ 2y = 10

⇒ y = 102\dfrac{10}{2}

⇒ y = 5.

Hence, option 2 is the correct option.

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