Mathematics
Given 20 - 5x < 5(x + 8), find the smallest value of x when :
(i) x ∈ I
(ii) x ∈ W
(iii) x ∈ N
Linear Inequations
15 Likes
Answer
Solving,
⇒ 20 - 5x < 5(x + 8)
⇒ 20 - 5x < 5x + 40
⇒ 5x + 5x > 20 - 40
⇒ 10x > -20
⇒ x > = -2.
(i) As, x > -2 and x ∈ I.
∴ x = {-1, 0, 1 …….}
The smallest no. = -1.
Hence, smallest value of x = -1, when x is an integer.
(ii) As, x > -2 and x ∈ W.
∴ x = {0, 1, 2 …….}
The smallest no. = 0.
Hence, smallest value of x = 0, when x is a whole number.
(iii) As, x > -2 and x ∈ N.
∴ x = {1, 2 …….}
The smallest no. = 1.
Hence, smallest value of x = 1, when x is a natural number.
Answered By
8 Likes
Related Questions
Find the values of x, which satisfy the inequation :
; x ∈ N
Graph the solution set on the real number line.
State for each of the following statements whether it is true or false :
(a) If (x - a)(x - b) < 0, then x < a and x < b.
(b) If a < 0 and b < 0, then (a + b)2 > 0.
(c) If a and b are any two integers such that a > b, then a2 > b2.
(d) If p = q + 2, then p > q.
(e) If a and b are two negative integers such that a < b, then
If x ∈ Z, solve : 2 + 4x < 2x - 5 ≤ 3x. Also, represent its solution on the real number line.
If P = {x : 7x - 4 > 5x + 2, x ∈ R} and Q = {x : x - 19 ≥ 1 - 3x, x ∈ R}; find the range of set P ∩ Q and represent it on a number line.