In the given figure, ∠B = 60°, AB = 16 cm and BC = 23 cm. Calculate : (i) BE (ii) AC.

(i) In Δ ABE, Hence, BE = 8 cm. (ii) In Δ ABE, according to Pythagoras theorem, ⇒ AB2 = BE2 \+ EA2 (∵ AB is hypotenuse) ⇒ 162 = 82 \+ EA2 ⇒ 256 = 64 \+ EA2 ⇒ EA2 = 256 \- 64 ⇒ EA2 = 192 ⇒ EA = ⇒ EA = 8 EC = BC \- BE = 23 - 8 cm = 15 cm In Δ AEC, according to Pythagoras theorem, ⇒ AC2 = AE2 \+ EC2 (∵ AC is hypotenuse) ⇒ AC2 = (8 )2 \+ 152 ⇒ AC2 = 192 \+ 225 ⇒ AC2 = 417 ⇒ AC = = 20.42 cm Hence, AC = 20.42 cm.

Find the length of AB.

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In the given figure, AB and EC are parallel to each other. Sides AD and BC are 2 cm each and are perpendicular to AB.
Given that ∠AED = 60° and ∠ACD = 45°; calculate :
(i) AB
(ii) AC
(iii) AE

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Find :
(i) BC
(ii) AD
(iii) AC

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Mathematics

In the given figure, ∠B = 60°, AB = 16 cm and BC = 23 cm. Calculate :
(i) BE
(ii) AC.

Trigonometric Identities

Related Questions

Find the length of AB.

In the given figure, AB and EC are parallel to each other. Sides AD and BC are 2 cm each and are perpendicular to AB.
Given that ∠AED = 60° and ∠ACD = 45°; calculate :
(i) AB
(ii) AC
(iii) AE

Find :
(i) BC
(ii) AD
(iii) AC

Mathematics

In the given figure, ∠B = 60°, AB = 16 cm and BC = 23 cm. Calculate :(i) BE(ii) AC.

Trigonometric Identities

Related Questions

Find the length of AB.

In the given figure, AB and EC are parallel to each other. Sides AD and BC are 2 cm each and are perpendicular to AB.Given that ∠AED = 60° and ∠ACD = 45°; calculate :(i) AB(ii) AC(iii) AE

Find :(i) BC(ii) AD(iii) AC

In the given figure, ∠B = 60°, AB = 16 cm and BC = 23 cm. Calculate :
(i) BE
(ii) AC.

In the given figure, AB and EC are parallel to each other. Sides AD and BC are 2 cm each and are perpendicular to AB.
Given that ∠AED = 60° and ∠ACD = 45°; calculate :
(i) AB
(ii) AC
(iii) AE

Find :
(i) BC
(ii) AD
(iii) AC