If 2a - b + c = 0, prove 4a2 - b2 + c2 + 4ac = 0
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Given, 2a - b + c = 0⇒ (2a + c) = b
On squaring both sides,
(2a + c)2 = b2
⇒ 4a2 + c2 + 2(2a)(c) = b2
⇒ 4a2 - b2 + c2 + 4ac = 0
Hence proved.
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