If a + b + 2c = 0, prove that a 3 + b 3 + 8c 3 = 6abc

We know that if a + b + c = 0 then a 3 + b 3 + c 3 = 3abc Given, a + b + 2c = 0 ∴ (a) 3 + (b) 3 + (2c) 3 = 3(a)(b)(2c) ⇒ a 3 + b 3 + 8c 3 = 6abc Hence Proved.

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Mathematics

If a + b + 2c = 0, prove that a³ + b³ + 8c³ = 6abc

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We know that if a + b + c = 0 then a³ + b³ + c³ = 3abc

Given,

a + b + 2c = 0

∴ (a)³ + (b)³ + (2c)³ = 3(a)(b)(2c)

⇒ a³ + b³ + 8c³ = 6abc

Hence Proved.

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Mathematics

If a + b + 2c = 0, prove that a³ + b³ + 8c³ = 6abc

Expansions

Answer

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Mathematics

If a + b + 2c = 0, prove that a3 + b3 + 8c3 = 6abc

Expansions

Answer

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