If a + b + c = 0, then find the value of $\dfrac{a^2}{bc} + \dfrac{b^2}{ca} + \dfrac{c^2}{ab}$.

We know if a + b + c = 0, a³ + b³ + c³ = 3abc.

On dividing each side by abc,
$\phantom{\Rightarrow} \dfrac{a^3}{abc} + \dfrac{b^3}{abc} + \dfrac{c^3}{abc} = \dfrac{3abc}{abc} \\[1em] \Rightarrow \dfrac{a^2}{bc} + \dfrac{b^2}{ca} + \dfrac{c^2}{ab} = 3$

∴ Value of $\bold{\dfrac{a^2}{bc} + \dfrac{b^2}{ca} + \dfrac{c^2}{ab} = 3}$