If a - b = 6 and ab = 16, find a2 + b2
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Using the formula,
[∵(x - y)2 = x2 - 2xy + y2]
So,
(a - b)2 = a2 - 2ab + b2
Putting the value, a - b = 6 and ab = 16
⇒ (6)2 = a2 - 2 x 16 + b2
⇒ 36 = a2 - 32 + b2
⇒ a2 + b2 = 36 + 32
⇒ a2 + b2 = 68
Hence, the value of (a2 + b2) is 68.
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