If cos 62° 40' = x, the value of 1 + sin² 27° 20' is :

1. 1 + x²

2. 1 - x²

3. x² - 1

4. 1 + x

Given,

⇒ cos 62° 40' = x

⇒ cos (90° - 27° 20') = x

⇒ sin 27° 20' = x

Substituting value of sin 27° 20' in 1 + sin² 27° 20', we get :

⇒ 1 + sin² 27° 20' = 1 + x².

Hence, Option 1 is the correct option.