If log 5 x = y, find 5 2y + 3 in terms of x.

Given, ⇒ log 5 x = y ⇒ x = 5 y ......(1) Solving, equation 5 2y + 3 , we get : ⇒ 5 2y .5 3 ⇒ (5 y ) 2 × 125 Substituting value of 5 y from equation (1) in above equation, we get : ⇒ 125x 2 . Hence, 5 2y + 3 = 125x 2 .

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Mathematics

If log₅ x = y, find 5^{2y + 3} in terms of x.

Logarithms

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Answer

Given,

⇒ log₅ x = y

⇒ x = 5^y ……(1)

Solving, equation 5^{2y + 3}, we get :

⇒ 5^2y.5³

⇒ (5^y)² × 125

Substituting value of 5^y from equation (1) in above equation, we get :

⇒ 125x².

Hence, 5^{2y + 3} = 125x².

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Mathematics

If log₅ x = y, find 5^{2y + 3} in terms of x.

Logarithms

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