If the replacement set is the set of real numbers, solve :
8 - 3x ≤ 20
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⇒ -3x ≤ 20 - 8
⇒ -3x ≤ 12
Dividing both sides by -3 we get.
⇒ x ≥ -4 (As on dividing by negative no. the sign reverses.)
∴ Solution set = {x : x ∈ R and x ≥ -4}.
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If 25 - 4x ≤ 16, find :
(i) the smallest value of x when x is a real number,
(ii) the smallest value of x when x is an integer.
-4x ≥ -16
Find the largest value of x for which
2(x - 1) ≤ 9 - x and x ∈ W.