In the figure, given below, AB = AC. Prove that : ∠BOC = ∠ACD.
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In the following figure, AB = AC; BC = CD and DE is parallel to BC. Calculate :
(i) ∠CDE
(ii) ∠DCE
Calculate x :
(i)
(ii)
In the figure given below, LM = LN; angle PLN = 110°. Calculate :
(i) ∠LMN
(ii) ∠MLN
An isosceles triangle ABC has AC = BC. CD bisects AB at D and ∠CAB = 55°. Find :
(i) ∠DCB
(ii) ∠CBD
