In the given figure; BE = DC, then :

1. AD = DC

2. AE = BE

3. AD = AE

4. ∠ABE = ∠DAC

From figure,

⇒ AB = AC

∴ ∠B = ∠C (Angles opposite to equal sides are equal)

Given,

⇒ BE = DC

⇒ BD + DE = DE + EC

⇒ BD = EC.

In △ ABD and △ AEC,

⇒ BD = EC (Proved above)

⇒ AB = AC (Given)

⇒ ∠B = ∠C (Proved above)

∴ △ ABD ≅ △ AEC (By S.A.S. axiom)

We know that,

Corresponding parts of congruent triangle are equal.

∴ AD = AE.

Hence, Option 3 is the correct option.