In the given figure, OABC is a square of side 14 cm. Taking $π = \dfrac{22}{7}$, the area of the shaded portion is :

1. 154 cm²

2. 196 cm²

3. 42 cm²

4. 52 cm²

Side of the square = Radius of the circle = 14 cm

Area of shaded portion = Area of square - $\dfrac{1}{4}$ Area of quarter circle

$= Side^2 - \dfrac{1}{4} πr^2\\[1em] = 14^2 - \dfrac{1}{4} \times \dfrac{22}{7} \times 14^2\\[1em] = 196 - \dfrac{22}{28}\times 14 \times 14\\[1em] = 196 - \dfrac{22}{2} \times 14\\[1em] = 196 - \dfrac{308}{2} \\[1em] = 196 - 154\\[1em] = 42\text{cm}^2$

The area of the shaded portion is 42 cm².

Hence, option 3 is the correct option.