Mathematics
In the given figure, the value of AB × CD is :
AC × BC
AC × CD
AC × AB
AC2 + BC2
Related Questions
In △ ABC, ∠C = 90° and AC = BC, then AB2 is equal to :
AC2
2AC2
BC2
2BC2 - AC2
In the given diagram, AE2 + BD2 is equal to :
AB2 - DE2
DE2 - AB2
AB2 + DE2
DE × AB
ABC is an isosceles triangle right-angled at C. Then 2AC2 is equal to :
BC2
AC2
AC2 - BC2
AB2
In the figure, given below, AD ⊥ BC. Prove that :
c2 = a2 + b2 - 2ax.
