Physics

In transferring 1.5 C charge through a wire, 9 J of work is done. Find the potential difference across the wire.

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Given,

charge (q) = 1.5 C

work = 9 J

potential difference across the wire

$V = \dfrac{w}{q}$

Substituting the values in the formula, we get,

$V = \dfrac{9}{1.5} \\[0.5em] \Rightarrow V = 6 V$

Hence, the potential difference across the wire = 6 V.

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