A ladder 17 m long reaches the window of a building 15 m above the ground. Find the distance of the foot of the ladder from the building.
Pythagoras Theorem
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Question

A ladder 17 m long reaches the window of a building 15 m above the ground. Find the distance of the foot of the ladder from the building.

KnowledgeBoat · Accepted Answer

Let AB be the ladder, BC be the building and B be the window. Then, AB = 17 m, BC = 15 m AC be the distance of the foot of the ladder from the building. By Pythagoras theorem, Hypotenuse2 = Perpendicular2 + Base2 In triangle ABC, ⇒ AB2 = BC2 + AC2 ⇒ 172 = 152 + AC2 ⇒ 289 = 225 + AC2 ⇒ AC2 = 289 - 225 ⇒ AC2 = 64 ⇒ AC = ⇒ AC = 8 m. Hence, the distance of the foot of the ladder from the building is 8 m.

Mathematics

A ladder 17 m long reaches the window of a building 15 m above the ground. Find the distance of the foot of the ladder from the building.

Pythagoras Theorem

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