Prove that : (log a) 2 - (log b) 2 = log . log (ab)

To prove: (log a) 2 - (log b) 2 = log . log (ab) Solving L.H.S. of the above equation, we get : ⇒ (log a) 2 - (log b) 2 ⇒ (log a + log b)(log a - log b) ⇒ log ab. log Hence, proved that (log a) 2 - (log b) 2 = log . log (ab)

Simplify :
log (a)³ ÷ log a

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If log (a + b) = log a + log b, find a in terms of b.

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Prove that :
If a log b + b log a - 1 = 0, then b^a.a^b = 10

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If log (a + 1) = log (4a - 3) - log 3; find a.

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Mathematics

Prove that : (log a)<sup>2</sup> - (log b)<sup>2</sup> = log . log (ab)

Logarithms

Related Questions

Simplify :
log (a)³ ÷ log a

If log (a + b) = log a + log b, find a in terms of b.

Prove that :
If a log b + b log a - 1 = 0, then b^a.a^b = 10

If log (a + 1) = log (4a - 3) - log 3; find a.

Mathematics

Prove that : (log a)<sup>2</sup> - (log b)<sup>2</sup> = log . log (ab)

Logarithms

Related Questions

Simplify :log (a)3 ÷ log a

If log (a + b) = log a + log b, find a in terms of b.

Prove that :If a log b + b log a - 1 = 0, then ba.ab = 10

If log (a + 1) = log (4a - 3) - log 3; find a.

Simplify :
log (a)³ ÷ log a

Prove that :
If a log b + b log a - 1 = 0, then b^a.a^b = 10