Mathematics
In quadrilateral ABCD, AB = AD and CB = CD. Prove that AC is perpendicular bisector of BD.
Related Questions
Assertion (A): ΔABD ≅ ΔACE

Reason (R): ∠ADE + ∠ADB = ∠AEC + ∠AED
But AD = AE
⇒ ∠ADE = ∠AED
∴ ∠ADB = ∠AEC
⇒ ∠ABD ≅ ∠AEC
A is true, but R is false.
A is false, but R is true.
Both A and R are true and R is the correct reason for A.
Both A and R are true and R is the incorrect reason for A.
Which of the following pairs of triangles are congruent ? In each case, state the condition of congruency :
(a) In △ ABC and △ DEF, AB = DE, BC = EF and ∠B = ∠E.
(b) In △ ABC and △ DEF, ∠B = ∠E = 90°; AC = DF and BC = EF.
(c) In △ ABC and △ QRP, AB = QR, ∠B = ∠R and ∠C = ∠P.
(d) In △ ABC and △ PQR, AB = PQ, AC = PR and BC = QR.
(e) In △ ABC and △ PQR, BC = QR, ∠A = 90°, ∠C = ∠R = 40° and ∠Q = 50°.
In the given figure : AB // FD, AC // GE and BD = CE; prove that :
(i) BG = DF
(ii) CF = EG.

In a triangle ABC, AB = AC. Show that the altitude AD is median also.