Physics
A roller with a diameter of 0.2 m is raised over a pavement AB by applying forces F1 and F2, as shown in the diagram.
If the magnitude of both forces is 20 N, then compare the magnitudes of the torques produced by the two forces.
Force
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Answer
Anticlockwise torque is taken as positive, while clockwise torque is taken as negative according to the standard sign convention used in rotational motion analysis.
Here, for force F1, the axis of rotation will pass through point A.
Perpendicular distance = Diameter of roller = 0.2 m
So,
Clockwise torque due to F1 = -20 x 0.2 = -4 N m
For force F2, the axis of rotation will pass through point O.
Perpendicular distance = Radius of roller = = 0.1 m
So,
Clockwise torque due to F2 = -20 x 0.1 = -2 N m
Ratio of torques =
Ratio of torques = F1 : F2 = 2 : 1
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