Show that : sin 42° sec 48° + cos 42° cosec 48° = 2

Question

KnowledgeBoat · Accepted Answer

sin 42° sec 48° + cos 42° cosec 48° = 2 L.H.S. = sin 42° sec 48° + cos 42° cosec 48° = sin (90° - 48°) sec 48° + cos (90° - 48°) cosec 48° = cos 48° sec 48° + sin 48° cosec 48° = = = 1 + 1 = 2 R.H.S. = 2 ∴ L.H.S. = R.H.S. Hence, sin 42° sec 48° + cos 42° cosec 48° = 2.

Mathematics

Show that :
sin 42° sec 48° + cos 42° cosec 48° = 2

Trigonometric Identities

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Show that :
tan 10° tan 15° tan 75° tan 80° = 1

Express the following in terms of angles between 0° and 45° :
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Express the following in terms of angles between 0° and 45° :
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Mathematics

Show that :sin 42° sec 48° + cos 42° cosec 48° = 2

Trigonometric Identities

Related Questions

Show that :tan 10° tan 15° tan 75° tan 80° = 1

Express the following in terms of angles between 0° and 45° :sin 59° + tan 63°

Express the following in terms of angles between 0° and 45° :cosec 68° + cot 72°

Show that :
sin 42° sec 48° + cos 42° cosec 48° = 2

Show that :
tan 10° tan 15° tan 75° tan 80° = 1

Express the following in terms of angles between 0° and 45° :
sin 59° + tan 63°

Express the following in terms of angles between 0° and 45° :
cosec 68° + cot 72°