Show that : sin 42° sec 48° + cos 42° cosec 48° = 2

Question

KnowledgeBoat · Accepted Answer

Solving L.H.S. of the equation : ⇒ sin 42° sec (90 - 42)° + cos 42° cosec (90 - 42)° By formula, sec (90° - A) = cosec A and cosec (90° - A) = sec A. ⇒ sin 42° cosec 42° + cos 42° sec 42° ⇒ sin 42° + cos 42° ⇒ 1 + 1 ⇒ 2. Since, L.H.S. = R.H.S. Hence, proved that sin 42° sec 48° + cos 42° cosec 48° = 2.

Mathematics

Show that :
sin 42° sec 48° + cos 42° cosec 48° = 2

Trigonometric Identities

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