KnowledgeBoat Logo
|

Mathematics

Solve the following inequation, write the solution set and represent it on the real number line.

2x53<3x5+104x5+11; xR2x - \dfrac{5}{3} \lt \dfrac{3x}{5} + 10 \le \dfrac{4x}{5} + 11;\ x \in R

Linear Inequations

10 Likes

Answer

Solving L.H.S of the equation 2x53<3x5+104x5+11; xR2x - \dfrac{5}{3} \lt \dfrac{3x}{5} + 10 \le \dfrac{4x}{5} + 11 ;\ x \in R we get,

2x53<3x5+106x53<3x+505Multiplying both side by 15, we get:15(6x53)<15(3x+505)5(6x5)<3(3x+50)30x25<9x+15030x9x<25+15021x<175x<17521x<253 ……..(1)\Rightarrow 2x - \dfrac{5}{3} \lt \dfrac{3x}{5} + 10 \\[1em] \Rightarrow \dfrac{6x - 5}{3} \lt \dfrac{3x + 50}{5} \\[1em] \text{Multiplying both side by 15, we get:} \\[1em] \Rightarrow 15\Big(\dfrac{6x - 5}{3}\Big) \lt 15\Big(\dfrac{3x + 50}{5}\Big) \\[1em] \Rightarrow 5(6x - 5) \lt 3(3x + 50) \\[1em] \Rightarrow 30x - 25 \lt 9x + 150 \\[1em] \Rightarrow 30x - 9x \lt 25 + 150 \\[1em] \Rightarrow 21x \lt 175 \\[1em] \Rightarrow x \lt \dfrac{175}{21} \\[1em] \Rightarrow x \lt \dfrac{25}{3} \text{ ……..(1)}

Solving R.H.S of the equation 2x53<3x5+104x5+11; xR2x - \dfrac{5}{3} \lt \dfrac{3x}{5} + 10 \le \dfrac{4x}{5} + 11 ;\ x \in R we get,

3x5+104x5+113x+5054x+555Multiplying both side by 5, we get:5(3x+505)5(4x+555)3x+504x+5550554x3x5xx5 ……..(2)\Rightarrow \dfrac{3x}{5} + 10 \le \dfrac{4x}{5} + 11 \\[1em] \Rightarrow \dfrac{3x + 50}{5} \le \dfrac{4x + 55}{5} \\[1em] \text{Multiplying both side by 5, we get:} \\[1em] \Rightarrow 5\Big(\dfrac{3x + 50}{5}\Big) \le 5\Big(\dfrac{4x + 55}{5}\Big) \\[1em] \Rightarrow 3x + 50 \le 4x + 55 \\[1em] \Rightarrow 50 - 55 \le 4x - 3x \\[1em] \Rightarrow -5 \le x \\[1em] \Rightarrow x \ge -5 \text{ ……..(2)}

From equation (1) and (2), we get :

-5 ≤ x < 253\dfrac{25}{3}.

Solve the following inequation, write the solution set and represent it on the real number line. ICSE 2025 Maths Solved Question Paper.

Hence, solution set equals to -5 ≤ x < 253\dfrac{25}{3}, x ∈ R.

Answered By

6 Likes


Related Questions