Solve the following linear equations: (i) 5(x + 1) = 25 (ii) 2(3x − 1) = 10 (iii)

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(i) We have: 5(x + 1) = 25 ⇒ x + 1 = 5 [Dividing both sides by 5] ⇒ x = 5 − 1 [Transposing +1 to RHS] ∴ x = 4. (ii) We have: 2(3x − 1) = 10 ⇒ 3x − 1 = 5 [Dividing both sides by 2] ⇒ 3x = 5 + 1 [Transposing −1 to RHS] ⇒ 3x = 6 ⇒ ∴ x = 2. (iii) We have: ⇒ 3x − 1 = 11 × 4 [Multiplying both sides by 4] ⇒ 3x − 1 = 44 ⇒ 3x = 44 + 1 = 45 ⇒ x = ⇒ x = 15 ∴ x = 15.

Mathematics

Solve the following linear equations: (i) 5(x + 1) = 25 (ii) 2(3x − 1) = 10 (iii)

Simple Equations

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