Solve the following equation:

2x² - 3x + 1 = 0

Given, 2x² - 3x + 1 = 0.

⇒ 2x² - 2x - x + 1 = 0

⇒ 2x(x - 1) - 1(x - 1) = 0

⇒ (x - 1)(2x - 1) = 0

⇒ x - 1 = 0 or 2x - 1 = 0

⇒ x = 1 or x = $\dfrac{1}{2}$.

Hence, roots of the given equations are 1, $\dfrac{1}{2}$.