Solve the following equation:

6 + x = x²

Given, 6 + x = x²

⇒ x² - x - 6 = 0

⇒ x² - 3x + 2x - 6 = 0

⇒ x(x - 3) + 2(x - 3) = 0

⇒ (x - 3)(x + 2) = 0

⇒ x - 3 = 0 or x + 2 = 0

⇒ x = 3 or x = -2.

Hence, roots of the given equations are -2, 3.