Solve the following equation:
log(3x + 2) + log(3x - 2) = 5log 2
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Given,
⇒ log(3x + 2) + log(3x - 2) = 5log 2
⇒ log(3x + 2)(3x - 2) = log 25
⇒ log(9x2 - 4) = log 32
⇒ 9x2 - 4 = 32
⇒ 9x2 = 36
⇒ x2 = 4
⇒ x = 2.
Hence, x = 2.
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log(4y - 3) = log(2y + 1) - log 3
log10(x + 2) + log10(x - 2) = log103 + 3log104
Solve for x: log3(x + 1) - 1 = 3 + log3(x - 1)
Solve for x: 5log x + 3log x = 3log x + 1 - 5log x - 1.