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Physics

A spirit lamp supplying heat at a rate of 50 W is used to melt 0.025 kg of ice at 0 °C taken in a container. If all the ice in the container is melted in 168 s, then what is the specific latent heat of fusion of ice?

(The heat capacity of the container is negligible.)

Calorimetry

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Answer

Given,

  • Power of spirit lamp (P) = 50 W
  • Mass of ice (m) = 0.025 kg
  • Fixed temperature (Ti) = 0 °C
  • Time Taken (t) = 168 s

Let specific latent heat of ice be Li.

Now,

Heat gained by ice (Q) = P x t = 50 x 168 = 8400 J

Also,

Li = Qm=84000.025=840000025\dfrac {\text Q}{\text m} = \dfrac {8400}{0.025}= \dfrac{8400000}{25} = 336 x 103 J kg-1

Hence, specific latent heat of fusion of ice is 336 x 103 J kg-1.

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