Subtract hexa-decimal number (A68D) 16 from (D53F) 16

Therefore, (D53F) 16 - (A68D) 16 = (2EB2) 16 Explanation: 1. F - D = 15 - 13 = 2. 2. 3 - 8, here 8 is greater than 3 so we borrow 1 from next significant digit 5 and it becomes 4. Now 3 becomes 3 + 16 = 19 and 19 - 8 = 11 or B. 3. 4 - 6, here again 6 is greater than 4 so we borrow 1 from next significant digit D and it becomes C. Now 4 becomes 4 + 16 = 20 and 20 - 6 = 14 or E. 4. C - A = 12 - 10 = 2.

Subtract octal number (2546)₈ from (5142)₈

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Add hexa-decimal numbers (1F5C)₁₆ and (AC2B)₁₆

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Subtract hexa-decimal number (ABCD)₁₆ from (EA9C)₁₆

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Multiply the following binary numbers:
(10110)₂ x (110)₂

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Subtract hexa-decimal number (A68D)₁₆ from (D53F)₁₆

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Subtract octal number (2546)₈ from (5142)₈

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Multiply the following binary numbers:
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Computer Science

Subtract hexa-decimal number (A68D)16 from (D53F)16

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Subtract hexa-decimal number (A68D)₁₆ from (D53F)₁₆

Subtract octal number (2546)₈ from (5142)₈

Add hexa-decimal numbers (1F5C)₁₆ and (AC2B)₁₆

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Multiply the following binary numbers:
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