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Mathematics

The altitude and the base of a triangular field are in the ratio 6 : 5. If its cost is ₹ 49,57,200 at the rate of ₹ 36,720 per hectare and 1 hectare = 10,000 sq.m, find (in metre) the dimensions of the field.

Area Trapezium Polygon

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Answer

Given:

Ratio of altitude and base of the field = 6 : 5

Total cost = ₹ 49,57,200

Rate = ₹ 36,720 per hectare

As we know that area of the triangular field x rate = total cost

⇒ Area of the triangular field x 36,7201,00,00\dfrac{₹ 36,720}{1,00,00} = ₹ 49,57,200

⇒ Area of the triangular field = ₹ 49,57,20036,720×10,000\dfrac{49,57,200}{36,720} \times 10,000

⇒ Area of the triangular field = ₹ 135×10,000135 \times 10,000

⇒ Area of the triangular field = 13,50,000 m2

Let the altitude be 6a and the base be 5a.

The altitude and the base of a triangular field are in the ratio 6 : 5. If its cost is ₹ 49,57,200 at the rate of ₹ 36,720 per hectare and 1 hectare = 10,000 sq.m, find (in metre) the dimensions of the field. Area of a Trapezium and a Polygon, Concise Mathematics Solutions ICSE Class 8.

As we know, the area of a triangle = 12\dfrac{1}{2} x base x height

⇒ 13,50,000 = 12\dfrac{1}{2} x 6a x 5a

⇒ 13,50,000 = 12\dfrac{1}{2} x 30a2

⇒ 13,50,000 = 15a2

⇒ a2 = 13,50,00015\dfrac{13,50,000}{15}

⇒ a2 = 90000

⇒ a = 90000\sqrt{90000}

⇒ a = 300

So, the altitude = 6a

= 6 x 300

= 1800 m

And, the base = 5a

= 5 x 300

= 1500 m

Hence, the dimensions of the field are 1800 m and 1500 m.

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