The circumference of a circular table is 88 m. Find its area.

Given:

The circumference of a circular table = 88 m

Let r be the radius of the circle.

As we know, the circumference of the circle = 2πr

$⇒ 2 \times \dfrac{22}{7} \times r = 88\\[1em] ⇒ \dfrac{44}{7} \times r = 88\\[1em] ⇒ r = \dfrac{88 \times 7}{44}\\[1em] ⇒ r = \dfrac{616}{44}\\[1em] ⇒ r = 14 \text{ m}$

The area of the circle = πr²

$= \dfrac{22}{7} \times 14^2\\[1em] = \dfrac{22}{7} \times 196\\[1em] = \dfrac{4,312}{7}\\[1em] = 616 \text{ m}^2$

Hence, the area of the circular table is 616 m².