The given figure shows the cross-section of a concrete structure. Calculate the area of cross-section if AB = 1.8 m, CD = 0.6 m, DE = 0.8 m, EF = 0.3 m and AF = 1.2 m.

Given:

AB = 1.8 m, CD = 0.6 m, DE = 0.8 m, EF = 0.3 m and AF = 1.2 m

Area of ABCDEF = Area of rectangle AGEF + Area of rectangle GHCD + Area of triangle HBC.

Area of rectangle AGEF = l x b = AF x EF

= 1.2 x 0.3 m²

= 0.36 m²

Area of rectangle GHCD = l x b = GH x HC

= 0.6 x 2 m² (HC = AF + ED = 1.2 + 0.8 = 2 cm)

= 1.2 m²

Area of triangle HBC = $\dfrac{1}{2}$ x b x h = $\dfrac{1}{2}$ x HB x HC

= $\dfrac{1}{2}$ x 0.9 x 2 m² (HB = AB - AH = 1.8 - 0.9 = 0.9)

= 0.9 x 1 m²

= 0.9 m²

Now, area of ABCDEF = 0.36 m² + 1.2 m² + 0.9 m²

= 2.46 m²

Hence, the area of cross-section is 2.46 sq. m.