Calculate the area of the figure given below which is not drawn to scale.

Area of figure ABCEF = Area of trapezium ABCF + Area of triangle CEF

Area of triangle CEF = $\dfrac{1}{2}$ x b x h = $\dfrac{1}{2}$ x CF x DE

= $\dfrac{1}{2}$ x 25 x 12 m²

= 25 x 6 m²

= 150 m²

In triangle BGC,

Base² + Height² = Hypotenuse²

⇒ CG² + BG² = CB²

Let h be the length of BG.

⇒ 10² + h² = 26² (∵CG = CF - GF = CF - BA = 25 - 15 = 10)

⇒ 100 + h² = 676

⇒ h² = 676 - 100

⇒ h² = 576

⇒ h = $\sqrt{576}$

⇒ h = 24 cm

Area of trapezium = $\dfrac{1}{2}$ (sum of parallel sides) x distance between the parallel sides

= $\dfrac{1}{2}$ (AB + CF) x BG

= $\dfrac{1}{2}$ (15 + 25) x 24 m²

= $\dfrac{1}{2}$ x 40 x 24 m²

= 20 x 24 m²

= 480 m²

So, total area of figure ABCEF = 150 + 480 m²

= 630 m²

Hence, the area is 630 m².