The length of a rectangle is 16 cm and its perimeter is equal to the perimeter of a square with side 12.5 cm. Find the area of the rectangle.

Given:

The length of the rectangle is 16 cm.

The perimeter of the rectangle = The perimeter of a square.

The side of the square is 12.5 cm.

As we know, the perimeter of the square = 4 x side

= 4 x 12.5 cm

= 50 cm

Let the breadth of the rectangle be b cm.

And, the perimeter of the rectangle = 2 (length + breadth)

⇒ 2 (16 + b) = 50

⇒ 16 + b = $\dfrac{50}{2}$

⇒ 16 + b = 25

⇒ b = 25 - 16

⇒ b = 9 cm

Now, area of the rectangle = length x breadth

= 16 x 9 cm²

= 144 cm²

Hence, the area of the rectangle is 144 cm².