The quadratic equation has 1. two distinct real roots 2. two equal real roots 3. no real roots 4. more than two real roots

Question

KnowledgeBoat · Accepted Answer

In order to find nature of roots we need to find the value of, b² - 4ac Given, Comparing equation with ax² + bx + c = 0 a= 2 , b = - , c = 1 Putting values in b² - 4ac Since, b² - 4ac = -3 0 , hence there are no real roots ∴ Option 3 is the correct option.

Mathematics

The quadratic equation has 1. two distinct real roots 2. two equal real roots 3. no real roots 4. more than two real roots

Quadratic Equations

Related Questions

If the roots of equation x² - 6x + k = 0 are real and distinct, then value of k is :
> -9
> -6
< 6
< 9

The roots of the quadratic equation px² - qx + r = 0 are real and equal if :
(a) p² = 4qr
(b) q² = 4pr
(c) –q² = 4pr
(d) p² > 4qr

Mathematics

The quadratic equation has 1. two distinct real roots 2. two equal real roots 3. no real roots 4. more than two real roots

Quadratic Equations

Related Questions

If the roots of equation x2 - 6x + k = 0 are real and distinct, then value of k is :> -9> -6< 6< 9

The roots of the quadratic equation px2 - qx + r = 0 are real and equal if :(a) p2 = 4qr(b) q2 = 4pr(c) –q2 = 4pr(d) p2 > 4qr

If the roots of equation x² - 6x + k = 0 are real and distinct, then value of k is :
> -9
> -6
< 6
< 9

The roots of the quadratic equation px² - qx + r = 0 are real and equal if :
(a) p² = 4qr
(b) q² = 4pr
(c) –q² = 4pr
(d) p² > 4qr