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Mathematics

If three different coins are tossed together, find the probability of getting two heads.

  1. (38)\Big(\dfrac{3}{8}\Big)

  2. (12)\Big(\dfrac{1}{2}\Big)

  3. (34)\Big(\dfrac{3}{4}\Big)

  4. (58)\Big(\dfrac{5}{8}\Big)

Probability

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Answer

When three coins are tossed together, the possible outcomes are: {(H, H, H), (H, H, T), (H, T, H), (T, H, H), (H, T, T), (T, H, T), (T, T, H), (T, T, T)}

Total number of outcomes = 8

Let E be the event of getting exactly two heads,

E = {(H, H, T), (H, T, H), (T, H, H)}

The number of favorable outcomes to the event E = 3

∴ P(E) = Number of favorable outcomesTotal number of outcomes=38\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{3}{8}

Hence, option 1 is the correct option.

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