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Mathematics

Two fair coins are tossed simultaneously. What is the probability of getting at most one tail?

  1. (14)\Big(\dfrac{1}{4}\Big)

  2. (12)\Big(\dfrac{1}{2}\Big)

  3. (34)\Big(\dfrac{3}{4}\Big)

  4. (38)\Big(\dfrac{3}{8}\Big)

Probability

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Answer

When two coins are tossed simultaneously, the possible outcomes are: {(H, H), (H, T), (T, H), (T, T)}

Total number of outcomes = 4

Let E be the event of getting at most one tail,

E = {(H, H), (H, T), (T, H)}

The number of favorable outcomes to the event E = 3

∴ P(E) = Number of favorable outcomesTotal number of outcomes=34\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{3}{4}

Hence, option 3 is the correct option.

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