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Mathematics

Three unbiased coins are tossed together. What is the probability of getting at least two heads?

  1. (12)\Big(\dfrac{1}{2}\Big)

  2. (58)\Big(\dfrac{5}{8}\Big)

  3. (34)\Big(\dfrac{3}{4}\Big)

  4. (78)\Big(\dfrac{7}{8}\Big)

Probability

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Answer

When three coins are tossed together, the possible outcomes are: {(H, H, H), (H, H, T), (H, T, H), (T, H, H), (H, T, T), (T, H, T), (T, T, H), (T, T, T)}

Total number of outcomes = 8

Let E be the event of getting at least two heads,

E={(H, H, H), (H, H, T), (H, T, H), (T, H, H)}

The number of favorable outcomes to the event E = 4

∴ P(E) = Number of favorable outcomesTotal number of outcomes=48=12\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{4}{8} = \dfrac{1}{2}

Hence, option 1 is the correct option.

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