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In triangle ABC, AD : DB = 2 : 3, DE is parallel to BC.

In triangle ABC, AD : DB = 2 : 3, DE is parallel to BC. Concise Mathematics Solutions ICSE Class 10.

Assertion (A) : DEBC=ADBD=23\dfrac{\text{DE}}{\text{BC}} = \dfrac{\text{AD}}{\text{BD}} = \dfrac{2}{3}.

Reason (R) : DEBC=ADAB=25\dfrac{\text{DE}}{\text{BC}} = \dfrac{\text{AD}}{\text{AB}} = \dfrac{2}{5}.

  1. A is true, R is false.

  2. A is false, R is true.

  3. Both A and R are true and R is correct reason for A.

  4. Both A and R are true and R is incorrect reason for A.

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Answer

Given,

AD : DB = 2 : 3

Let AD = 2x and DB = 3x.

From figure,

AB = AD + DB = 2x + 3x = 5x.

In Δ ADE and Δ ABC

⇒ ∠DAE = ∠BAC (Common angle)

⇒ ∠ADE = ∠ABC (Corresponding angles are equal)

⇒ ∠AED = ∠ACB (Corresponding angles are equal)

∴ ΔADE ∼ ΔABC (By AAA postulate)

We know that,

In similar triangles, corresponding sides are proportional (or in the same ratio).

DEBC=ADABDEBC=2x5x=25.\therefore \dfrac{DE}{BC} = \dfrac{AD}{AB} \\[1em] \Rightarrow \dfrac{DE}{BC} = \dfrac{2x}{5x} = \dfrac{2}{5}.

∴ Assertion (A) is false, reason (R) is true.

Hence, option 2 is the correct option.

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