Using the information in the following figure, find the area of the trapezium.

Draw a perpendicular line CP on AB, such that CP = 9 m and AP = 23 m. Let PB = `a` m In Δ CPB, by using the Pythagoras theorem, Base 2 \+ Height 2 = Hypotenuse 2 ⇒ a 2 \+ (9) 2 = (15) 2 ⇒ a 2 \+ 81 = 225 ⇒ a 2 = 225 \- 81 ⇒ a 2 = 144 ⇒ a 2 = 144 ⇒ a = ⇒ a = 12 m So, AB = AP \+ PB = 23 \+ 12 = 35 m Area of trapezium = (sum of parallel sides) x height = (23 \+ 35) x 9 = x 58 x 9 = 29 x 9 = 261 m 2 Hence, the area of the trapezium is 261 m 2 .

The perimeter of a triangle is 450 m and its sides are in the ratio 12 : 5 : 13. Find the area of the triangle.

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A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 26 cm, 28 cm and 30 cm and the parallelogram stands on the base 28 cm, find the height of the parallelogram.

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Sum of the areas of two squares is 400 cm². If the difference of their perimeters is 16 cm, find the sides of the two squares.

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Mathematics

Using the information in the following figure, find the area of the trapezium.

Mensuration

Related Questions

The perimeter of a triangle is 450 m and its sides are in the ratio 12 : 5 : 13. Find the area of the triangle.

A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 26 cm, 28 cm and 30 cm and the parallelogram stands on the base 28 cm, find the height of the parallelogram.

Sum of the areas of two squares is 400 cm². If the difference of their perimeters is 16 cm, find the sides of the two squares.

Mathematics

Using the information in the following figure, find the area of the trapezium.

Mensuration

Related Questions

The perimeter of a triangle is 450 m and its sides are in the ratio 12 : 5 : 13. Find the area of the triangle.

A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 26 cm, 28 cm and 30 cm and the parallelogram stands on the base 28 cm, find the height of the parallelogram.

Sum of the areas of two squares is 400 cm2. If the difference of their perimeters is 16 cm, find the sides of the two squares.

Sum of the areas of two squares is 400 cm². If the difference of their perimeters is 16 cm, find the sides of the two squares.