Without solving, comment upon the nature of roots of the following equation :

6x² - 13x + 4 = 0

Comparing 6x² - 13x + 4 = 0 with ax² + bx + c = 0 we get,

a = 6, b = -13 and c = 4.

We know that,

Discriminant = D = b² - 4ac = (-13)² - 4(6)(4)

= 169 - 96 = 73; which is positive.

Since, a, b and c are real numbers; a ≠ 0 and b² - 4ac > 0

∴ The roots are real and unequal.