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Model Question Paper

Model Question Paper 4

Class - 6 ML Aggarwal Understanding ICSE Mathematics



Questions

Question 1

Avanti's present age is y years and her mother's age is 4 years less than 3 times her age, then her mother's present age is

  1. (3y + 4) years

  2. (4y - 3) years

  3. (3y - 4) years

  4. 3(y - 4) years

Answer

Given:

Avanti's present age = y years

3 times Avanti's age = 3 × y = 3y years

Mother's age is 4 years less than 3 times Avanti's age.

∴ Mother's present age = (3y - 4) years

Hence, option 3 is the correct option.

Question 2

Which of the following statements is false?

  1. Every square is a rhombus.

  2. An equilateral triangle is a regular polygon.

  3. A triangle having all acute angles is scalene.

  4. Every square is a regular polygon.

Answer

Let us examine each statement:

  1. Every square is a rhombus — True, because a square has all four sides equal, which is the defining property of a rhombus.

  2. An equilateral triangle is a regular polygon — True, because all its sides are equal and all its angles are equal (each 60°).

  3. A triangle having all acute angles is scalene — False, because an equilateral triangle also has all acute angles (each 60°), but it is not scalene. So an acute-angled triangle can be scalene, isosceles or equilateral.

  4. Every square is a regular polygon — True, because all its sides are equal and all its angles are equal (each 90°).

Hence, option 3 is the correct option.

Question 3

If p = 3, q = 2 and r = 5, find the value of:

2p2 + 3q - r2 + 2pr - 5pqr

Answer

Given:

p = 3, q = 2, r = 5

Substituting the values in the given expression:

2p2 + 3q - r2 + 2pr - 5pqr

= 2(3)2 + 3(2) - (5)2 + 2(3)(5) - 5(3)(2)(5)

= 2 × 9 + 6 - 25 + 30 - 150

= 18 + 6 - 25 + 30 - 150

= 54 - 175

= -121

∴ The value of the expression is -121.

Question 4

Fill in the following blanks:

(i) A polygon is a closed simple curve made up of entirely .....

(ii) A cuboid has 6 rectangular faces, ..... edges and ..... vertices.

Answer

(i) A polygon is a closed simple curve made up of entirely line segments.

(ii) A cuboid has 6 rectangular faces, 12 edges and 8 vertices.

Question 5

In the monomial -3x2yz3, write

(i) the numerical coefficient

(ii) the literal coefficient

(iii) the coefficient of x2

(iv) the coefficient of 3xy.

Answer

Given monomial: -3x2yz3

(i) The numerical coefficient is the number multiplied with the literal part.

∴ Numerical coefficient = -3

(ii) The literal coefficient is the product of the variable factors.

∴ Literal coefficient = x2yz3

(iii) Coefficient of x2 = 3x2yz3x2\dfrac{-3x^2yz^3}{x^2} = -3yz3

∴ Coefficient of x2 = -3yz3

(iv) Coefficient of 3xy = 3x2yz33xy\dfrac{-3x^2yz^3}{3xy} = -xz3

∴ Coefficient of 3xy = -xz3

Question 6

Look at the following pattern of squares formed by matchsticks:

Look at the following pattern of squares formed by matchsticks. Model Question Paper 4, ML Aggarwal Understanding Mathematics Solutions ICSE Class 6.

Find the rule that gives the number of matchsticks required in terms of the number of squares formed.

Answer

Let us count the number of matchsticks for each pattern:

For 1 square, number of matchsticks required = 4

For 2 squares, number of matchsticks required = 4 + 3 = 7

For 3 squares, number of matchsticks required = 7 + 3 = 10

For 4 squares, number of matchsticks required = 10 + 3 = 13

We notice that the first square needs 4 matchsticks, and each new square added to the pattern requires 3 more matchsticks (because one side is shared with the previous square).

So, for n squares, number of matchsticks required = 4 + 3(n - 1)

= 4 + 3n - 3

= 3n + 1

∴ If n squares are formed, then the number of matchsticks required = 3n + 1.

Question 7

Name each of the following triangles in two ways (you may judge by observation or use ruler and protractor):

Name each of the following triangles in two ways (you may judge by observation or use ruler and protractor). Model Question Paper 4, ML Aggarwal Understanding Mathematics Solutions ICSE Class 6.

Answer

(i) On observation, one angle of the triangle is greater than 90° (obtuse angle), so it is an obtuse angled triangle. Also, all three sides of the triangle are of different lengths, so it is a scalene triangle.

∴ The triangle is an obtuse angled and scalene triangle.

(ii) On observation, one angle of the triangle is a right angle (90°), so it is a right angled triangle. Also, the two sides forming the right angle are equal in length, so it is an isosceles triangle.

∴ The triangle is an isosceles and right angled triangle.

Question 8

Draw a net of a regular tetrahedron.

Answer

A regular tetrahedron is a special triangular pyramid whose base and all four faces are equilateral triangles of the same size.

A regular tetrahedron has 4 triangular faces, 6 edges and 4 vertices.

To draw its net, we unfold it so that all 4 equilateral triangles lie flat in a plane. One common net consists of one equilateral triangle in the centre with three equilateral triangles attached to its three sides.

Draw a net of a regular tetrahedron. Model Question Paper 4, ML Aggarwal Understanding Mathematics Solutions ICSE Class 6.

Question 9

Solve the linear equation: 4 - 3(3x + 2) = 4(7 - 3x)

Also verify the solution.

Answer

Given equation:

4 - 3(3x + 2) = 4(7 - 3x)

Removing brackets on both sides:

⇒ 4 - 9x - 6 = 28 - 12x

⇒ -2 - 9x = 28 - 12x

⇒ -9x + 12x = 28 + 2

⇒ 3x = 30

⇒ x = 303\dfrac{30}{3}

⇒ x = 10

∴ x = 10

Verification:

Substituting x = 10 in the given equation:

LHS = 4 - 3(3 × 10 + 2)

= 4 - 3(30 + 2)

= 4 - 3 × 32

= 4 - 96

= -92

RHS = 4(7 - 3 × 10)

= 4(7 - 30)

= 4 × (-23)

= -92.

Since LHS = RHS, the solution x = 10 is verified.

Question 10

Use the adjoining figure to name:

(i) parallel lines

(ii) concurrent lines

(iii) collinear points

(iv) two opposite rays

Use the adjoining figure to name. Model Question Paper 4, ML Aggarwal Understanding Mathematics Solutions ICSE Class 6.

Answer

(i) Parallel lines: Two lines are parallel if they never meet however far they are extended.

From the figure, the parallel lines are AF\overleftrightarrow{AF}and CE\overleftrightarrow{CE}.

(ii) Concurrent lines: Three or more lines are said to be concurrent if they all pass through the same point.

From the figure, the lines BC\overleftrightarrow{BC}, CD\overleftrightarrow{CD}and CE\overleftrightarrow{CE}all pass through the point C, so they are concurrent lines.

(iii) Collinear points: Three or more points are said to be collinear if they all lie on the same straight line.

From the figure, the points A, B and C lie on the same line, so A, B and C are collinear points.

(iv) Two opposite rays: Two rays are opposite if they share the same endpoint and extend in exactly opposite directions, forming a straight line.

From the figure, the rays BC\overrightarrow{BC}and BA\overrightarrow{BA}have the common endpoint B and extend in opposite directions.

BC\overrightarrow{BC}and BA\overrightarrow{BA}are two opposite rays.

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