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Chapter 11

Quadrilaterals — Exercise 11(B)

Class - 9 RS Aggarwal Mathematics Solutions



Exercise 11B

Question 1

Construct a quadrilateral PQRS in which PQ = 4 cm, ∠P = 90°, QR = 4.3 cm, RS = 3.6 cm and SP = 3.2 cm.

Answer

Steps of constructions :

  1. Draw PQ = 4 cm.

  2. Draw ∠QPX = 90°.

  3. With P as centre and radius = 3.2 cm, draw an arc, cutting PX at S.

  4. With Q as centre and radius = 4.3 cm, draw an arc.

  5. With S as centre and radius = 3.6 cm, draw another arc, cutting the previous arc at R.

  6. Join QR and RS.

Construct a quadrilateral PQRS in which PQ = 4 cm, ∠P = 90°, QR = 4.3 cm, RS = 3.6 cm and SP = 3.2 cm. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, PQRS is the required quadrilateral.

Question 2

Construct a quadrilateral ABCD in which AB = 4.5 cm, BC = 5.2 cm, CD = 5 cm, DA = 4.7 cm and ∠ABC = 75°.

Answer

Steps of constructions:

  1. Draw AB = 4.5 cm.

  2. Draw ∠ABX = 75°.

  3. With B as centre and radius = 5.2 cm, draw an arc, cutting BX at C.

  4. With A as centre and radius = 4.7 cm, draw an arc.

  5. With C as centre and radius = 5 cm, draw another arc, cutting the previous arc at D.

  6. Join DC and DA.

Construct a quadrilateral ABCD in which AB = 4.5 cm, BC = 5.2 cm, CD = 5 cm, DA = 4.7 cm and ∠ABC = 75°. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is the required quadrilateral.

Question 3

Construct a quadrilateral ABCD in which AB = CD = 5.1 cm, BC = 4.7 cm, DA = 4.2 cm and ∠BCD = 60°.

Answer

Steps of constructions :

  1. Draw CD = 5.1 cm.

  2. Draw ∠DCX = 60°.

  3. With C as centre and radius = 4.7 cm, draw an arc, cutting CX at B.

  4. With D as centre and radius = 4.2 cm, draw an arc.

  5. With B as centre and radius = 5.1 cm, draw another arc, cutting the previous arc at A.

  6. Join DA and BA.

Construct a quadrilateral ABCD in which AB = CD = 5.1 cm, BC = 4.7 cm, DA = 4.2 cm and ∠BCD = 60°. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is the required quadrilateral.

Question 4

Construct a quadrilateral UVWZ in which UV = 6 cm, VW = 5.3 cm, UZ = 5 cm, ∠U = 60° and ∠V = 75°.

Answer

Steps of construction:

  1. Draw UV = 6 cm.

  2. Construct ∠VUX = 60°.

  3. With U as centre and radius = 5 cm, draw an arc, cutting UX at Z.

  4. Construct ∠UVY = 75°.

  5. With V as centre and radius = 5.3 cm,draw an arc, cutting arc VY at W.

  6. Join VW and ZW.

Construct a quadrilateral UVWZ in which UV = 6 cm, VW = 5.3 cm, UZ = 5 cm, ∠U = 60° and ∠V = 75°. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, UVWZ is required quadrilateral.

Question 5

Construct a quadrilateral PQRS in which PQ = 4.5 cm, QR = 5.6 cm, RS = 4.1 cm, ∠Q = 60° and ∠R = 120°.

Answer

Steps of construction:

  1. Draw QR = 5.6 cm.

  2. Construct ∠RQX = 60°.

  3. With Q as centre and radius = 4.5 cm, draw an arc, cutting QX at P.

  4. Construct ∠QRY = 120°.

  5. With R as centre and radius = 4.1 cm, draw an arc, cutting arc RY at S.

  6. Join SP.

Construct a quadrilateral PQRS in which PQ = 4.5 cm, QR = 5.6 cm, RS = 4.1 cm, ∠Q = 60° and ∠R = 120°. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, PQRS is required quadrilateral.

Question 6

Construct a quadrilateral ABCD in which AB = AD = 5.3 cm, BC = CD = 5 cm and diagonal BD = 6.4 cm.

Answer

Steps of construction :

  1. Draw AB = 5.3 cm.

  2. Taking A as center, draw an arc of radius 5.3 cm (= AD) and taking B as center, draw one more arc of radius 6.4 cm (= diagonal BD). Let the two arcs intersect at point D.

  3. Taking D as center, draw an arc of radius 5 cm (= CD) and taking B as center, draw one more arc of radius 5cm (= BC). Let the two arcs intersect at point C.

  4. Join DC and BC.

Construct a quadrilateral ABCD in which AB = AD = 5.3 cm, BC = CD = 5 cm and diagonal BD = 6.4 cm. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is the required quadrilateral.

Question 7

Construct a quadrilateral XYZT in which XY = XZ = 5.7 cm, YZ = 4.5 cm, ZT = 4.6 cm and XT = 5 cm.

Answer

Steps of construction:

  1. Draw YZ = 4.5 cm.

  2. With Y as centre and radius 5.7 cm draw an arc.

  3. With Z as centre and radius 5.7 cm draw another arc, cutting previous arc at X.

  4. With X as centre and radius 5 cm, draw an arc.

  5. With Z as centre and radius 4.6 cm draw another arc, cutting previous arc at T.

  6. Join XT and ZT.

Construct a quadrilateral XYZT in which XY = XZ = 5.7 cm, YZ = 4.5 cm, ZT = 4.6 cm and XT = 5 cm. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, XYZT is required quadrilateral.

Question 8

Construct a parallelogram ABCD in which BC = 6 cm, CD = 4 cm and ∠C = 60°.

Answer

Steps of construction:

  1. Draw BC = 6 cm.

  2. Construct ∠BCX = 60°.

  3. With C as centre and radius = 4 cm, draw an arc, cutting CX at D.

  4. With D as centre and radius = 6 cm, draw an arc.

  5. With B as centre and radius = 4 cm, draw another arc,cutting the previous arc at A.

  6. Join AB and DA.

Construct a parallelogram ABCD in which BC = 6 cm, CD = 4 cm and ∠C = 60°. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is the required parallelogram.

Question 9

Construct a parallelogram PQRS in which QR = 4.7 cm, ∠Q = 120° and PQ = 2.8 cm.

Answer

Steps of construction :

  1. Draw QR = 4.7 cm.

  2. Construct ∠RQX = 120°.

  3. With Q as centre and radius = 2.8 cm, draw an arc,cutting QX at P.

  4. With P as centre and radius = 4.7 cm, draw an arc.

  5. With R as centre and radius = 2.8 cm, draw another arc, cutting the previous arc at S.

  6. Join RS and PS.

Construct a parallelogram PQRS in which QR = 4.7 cm, ∠Q = 120° and PQ = 2.8 cm. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, PQRS is the required parallelogram.

Question 10

Construct a parallelogram ABCD in which BC = 5 cm, CD = 3 cm and diagonal BD = 6 cm.

Answer

Steps of construction:

  1. Draw BC = 5 cm.

  2. With B as centre and radius = 6 cm, draw an arc.

  3. With C as centre and radius = 3 cm, draw another arc, cutting previous arc at D.

  4. Join BD and CD.

  5. With B as centre and radius = 3 cm draw an arc.

  6. With D as centre and radius = 5 cm, draw another arc,cutting previous arc at A.

  7. Join AD and AB.

Construct a parallelogram ABCD in which BC = 5 cm, CD = 3 cm and diagonal BD = 6 cm. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is the required parallelogram.

Question 11

Construct a parallelogram ABCD in which AB = 4.8 cm, BC = 3.5 cm and diagonal AC = 5.4 cm.

Answer

Steps of construction :

  1. Draw AB = 4.8 cm.

  2. With A as centre and radius = 5.4 cm, draw an arc.

  3. With B as centre and radius = 3.5 cm, draw another arc, cutting previous arc at C.

  4. Join BC and AC.

  5. With A as centre and radius = 3.5 cm draw an arc.

  6. With C as centre and radius = 4.8 cm, draw another arc,cutting previous arc at D.

  7. Join AD and CD.

Construct a parallelogram ABCD in which AB = 4.8 cm, BC = 3.5 cm and diagonal AC = 5.4 cm. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is the required parallelogram.

Question 12

Construct a parallelogram ABCD in which diagonal AC = 5.6 cm, diagonal BD = 6.2 cm and angle between them is 60°.

Answer

Steps of construction:

  1. Draw AC = 5.6 cm.

  2. Find mid-point of AC.

  3. Construct ∠AOX = 60°, produce XO to Y.

  4. With O as centre and radii = 12\dfrac{1}{2} (6.2) = 3.1 cm, draw arcs, cutting OX at D and OY at B.

  5. Join AB, BC, CD and DA.

Construct a parallelogram ABCD in which diagonal AC = 5.6 cm, diagonal BD = 6.2 cm and angle between them is 60°. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is required parallelogram.

Question 13

Construct a rectangle whose adjacent sides are 4.7 cm and 3.2 cm.

Answer

Steps of construction :

  1. Draw AB = 4.7 cm.

  2. Construct ∠ABX = 90°.

  3. With B as centre and radius equal to 3.2 cm, draw an arc, cutting BX at C.

  4. With A as centre and radius = 3.2 cm, draw an arc.

  5. With C as centre and radius = 4.7 cm, draw an arc, cutting previous arc at D.

  6. Join DC and DA.

Construct a rectangle whose adjacent sides are 4.7 cm and 3.2 cm. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is required rectangle.

Question 14

Construct a rectangle ABCD in which AB = 4.5 cm and diagonal AC = 6 cm.

Answer

Steps of construction :

  1. Draw AB = 4.5 cm.

  2. Construct ∠ABX = 90°.

  3. With A as centre and radius equal to 6 cm, draw an arc, cutting BX at C. Join BC

  4. With C as centre and radius = 4.5 cm, draw an arc.

  5. With A as centre and radius = BC, draw an arc, cutting previous arc at D.

  6. Join DC and DA.

Construct a rectangle ABCD in which AB = 4.5 cm and diagonal AC = 6 cm. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is required rectangle.

Question 15

Construct a rectangle ABCD in which diagonal AC = 6.3 cm and the angle between the two diagonals is 50°.

Answer

Steps of construction :

  1. Draw AC = 6.3 cm.

  2. Find mid-point O of AC.

  3. Construct ∠AOX = 50°.

  4. Produce XO to Y.

  5. Set off OB = 3.15 cm and OD = 3.15 cm.

  6. Join AB, BC, CD and DA.

Construct a rectangle ABCD in which diagonal AC = 6.3 cm and the angle between the two diagonals is 50°. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is required rectangle.

Question 16

Construct a square one of whose diagonals measures 6 cm.

Answer

Steps of construction:

  1. Draw AC = 6 cm.

  2. Draw a perpendicular bisector XY of AC, meeting AC at O.

  3. On XY, setoff OD = 3 cm and OB = 3 cm.

  4. Join AD, CD, AB and BC.

Construct a square one of whose diagonals measures 6 cm. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is the required square.

Question 17

Construct a rhombus ABCD in which AB = 4.3 cm and ∠A = 45°.

Answer

Steps of construction :

  1. Draw AB = 4.3 cm.

  2. Construct ∠BAX = 45°.

  3. On AX, cut off AD = 4.3 cm.

  4. With B as centre and radius = 4.3 cm, draw an arc.

  5. With D as centre and radius = 4.3 cm, draw another arc, cutting the previous arc at C.

  6. Join CB and CD.

Construct a rhombus ABCD in which AB = 4.3 cm and ∠A = 45°.Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is the required rhombus.

Question 18

Construct a rhombus ABCD in which AB = 5 cm and diagonal AC = 6.8 cm.

Answer

Steps of construction:

  1. Draw AB = 5 cm.

  2. With A as centre and radius = 6.8 cm, draw an arc.

  3. With B as centre and radius = 5 cm, draw another arc, cutting the previous arc at C.

  4. Join BC and AC.

  5. With A as centre and radius = 5 cm, draw an arc.

  6. With C as centre and radius = 5 cm, draw another arc,cutting the previous arc at D.

  7. Join CD and DA.

Construct a rhombus ABCD in which AB = 5 cm and diagonal AC = 6.8 cm. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is required rhombus.

Question 19

Construct a rhombus ABCD in which diagonal AC = 5.8 cm and diagonal BD = 6.4 cm.

Answer

Steps of construction :

  1. Draw AC = 5.8 cm.

  2. Draw the perpendicular bisector XOY of AC.

  3. Set off OB = 3.2 cm on OY and OD = 3.2 cm on OX.

  4. Join AB, BC, CD and DA.

Construct a rhombus ABCD in which diagonal AC = 5.8 cm and diagonal BD = 6.4 cm. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is the required rhombus.

Question 20

Construct a square one of whose diagonals is 5.6 cm.

Answer

Steps of construction :

  1. Draw AC = 5.6 cm.

  2. Draw a perpendicular bisector XY of AC, meeting AC at O.

  3. On XY, setoff OD = 2.8 cm and OB = 2.8 cm.

  4. Join AD, CD, AB and BC.

Construct a square one of whose diagonals is 5.6 cm. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCD is the required square.

Question 21

Construct a regular hexagon of side 2 cm, using ruler and compasses only.

Answer

We know that each angle in a regular hexagon = 120°.

Steps of construction :

  1. Draw a line segment AB = 2 cm.

  2. At A and B, draw ∠ABC = 120° each and cut off AF = BC = 2 cm.

  3. At F and C, draw rays making angle of 120° each and cut off EF = CD = 2 cm.

  4. Join ED. Hence, ABCDEF is the required hexagon.

Construct a regular hexagon of side 2 cm, using ruler and compasses only. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCDEF is required regular hexagon.

Question 22

Construct a regular hexagon of side 3.5 cm, using ruler and compasses only.

Answer

We know that each angle in a regular hexagon = 120°.

Steps of construction :

  1. Draw a line segment AB = 3.5 cm.

  2. At A and B, draw ∠ABC = 120° each and cut off AF = BC = 3.5 cm.

  3. At F and C, draw rays making angle of 120° each and cut off EF = CD = 3.5 cm.

  4. Join ED. Hence, ABCDEF is the required hexagon.

Construct a regular hexagon of side 3.5 cm, using ruler and compasses only. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Hence, ABCDEF is required regular hexagon.

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