(2x + y)2 - (2y + x)2 is equal to:
3(x + y) (x - y)
2(x - y) (x + y)
2(y - x) (x + y)
(3x + y) (3x - y)
23 Likes
Using the formula
[∵ (x2 - y2) = (x + y)(x - y)]
(2x + y)2 - (2y + x)2
= ((2x + y) + (2y + x))((2x + y) - (2y + x))
= (2x + y + 2y + x)(2x + y - 2y - x)
= (2x + x + y + 2y)(2x - x + y - 2y)
= (3x + 3y)(x - y)
= 3(x + y)(x - y)
Hence, option 1 is the correct option.
Answered By
6 Likes
Factorise :
ax + 2bx + 3cx - 3a - 6b - 9c
2ab2c - 2a + 3b3c - 3b - 4b2c2 + 4c
49 - (x + 5)2 is equal to:
(54 - x) (54 + x)
(2 - x) (12 + x)
48(x + 5)2
48(x - 5)2
a2 - 2ab + b2 + a - b is equal to :
(a - b) (a + b - 1)
(a - b) (a + b + 1)
(a + b) (a - b - 1)
(a - b) (a - b + 1)