A gas occupies 500 cm³ at S.T.P. At what temperature will the volume of the gas be reduced by 20% of its original volume, pressure being constant?
Gas Laws
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A gas occupies 500 cm³ at S.T.P. At what temperature will the volume of the gas be reduced by 20% of its original volume, pressure being constant?

KnowledgeBoat · Accepted Answer

V₁ = Initial volume of the gas = 500 cm³ T₁ = Initial temperature of the gas = 273 K V₂ = Final volume of the gas = reduced by 20% of its original = 500 - ( x 500) = 500 - 100 = 400 cm³ T₂ = Final temperature of the gas = ? By Charles' Law: Substituting the values : Final temperature = 218.4 K

Chemistry

A gas occupies 500 cm³ at S.T.P. At what temperature will the volume of the gas be reduced by 20% of its original volume, pressure being constant?

Gas Laws

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Chemistry

A gas occupies 500 cm3 at S.T.P. At what temperature will the volume of the gas be reduced by 20% of its original volume, pressure being constant?

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