Mathematics
A man goes 40 m due north and then 50 m due west. Find his distance from the starting point.
Pythagoras Theorem
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Answer
Let A be the initial position of the man.

From figure,
ABC is a right-angled triangle.
By pythagoras theorem,
⇒ (Hypotenuse)2 = (Perpendicular)2 + (Base)2
⇒ AC2 = AB2 + BC2
⇒ AC2 = 402 + 502
⇒ AC2 = 1600 + 2500
⇒ AC2 = 4100
⇒ AC =
⇒ AC = 64.03 m.
Hence, distance from starting point is 64.03 meters.
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