Mathematics
ABCD is a trapezium with AB parallel to DC. Then the triangle similar to ΔAOB is:
ΔACB
ΔADB
ΔCOB
ΔCOD

Related Questions
In a ΔABC, AB = 10 cm, AC = 14 cm and BC = 6 cm. If AD is the internal bisector of ∠A, then CD is equal to:
3.5 cm
4.8 cm
7 cm
10.5 cm

In the given figure, two line segments AC and BD intersect each other at point P such that PA = 6 cm, PB = 3 cm, PC = 2.5 cm, PD = 5 cm, ∠APB = 50° and ∠CDP = 30°. Then ∠PBA = ?
30°
50°
60°
100°

The ratio of the corresponding sides of two similar triangles is 1 : 3. The ratio of their corresponding heights is :
1 : 3
1 : 9
3 : 1
9 : 1
If in triangles ABC and DEF, ∠A = ∠E = 40°, AB : ED = AC : EF and ∠F = 65°, then ∠B is equal to :
35°
65°
75°
85°